Class 12Subject Code: 043Year: 202433 Questions Available

CBSE Class 12 Chemistry 2024 — QuizCluster Solutions

Comprehensive question-by-question independently authored solutions for CBSE Class 12 Chemistry Board Examination (2024). Questions are referenced directly to the official CBSE Question Paper.

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Official Source & AttributionSource of question paper: Central Board of Secondary Education (CBSE)

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Q1 of 33

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Henry's Law Constant and Gas Solubility

Section A•1 Marks•Chapter: Solutions

Easy

Question 1 — Problem Statement (Synopsis)

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The value of Henry's law constant K_H for gas A is higher than that for gas B at the same temperature. Which gas will have higher solubility in water?

See Question 1 in official CBSE Class 12 Chemistry Question Paper (2024)

QuizCluster Step-by-Step Solution

Step 1: Henry's Law relationship

Henry's Law states: p = K_H · x, where p is partial pressure of gas and x is mole fraction (solubility) in liquid solution. Rearranging: x = p / K_H.

Step 2: Compare solubility at identical pressure

Since solubility x is inversely proportional to K_H (x ∝ 1/K_H), the gas with lower K_H value (Gas B) is more soluble in water.

Final Answer

Gas B has higher solubility (lower K_H value implies greater solubility)

Key Formulas & Mathematical Laws

Henry's Law: p = K_H · x
Solubility x ∝ 1 / K_H

Important Core Concept

K_H increases with increasing temperature, explaining why gases are less soluble in warm water (aquatic life thrives in cold water).

Common Student Pitfall

Assuming higher K_H means higher solubility.

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Question 1 of 33

Source of question paper: Central Board of Secondary Education (CBSE). QuizCluster provides independently prepared educational solutions and explanations. QuizCluster is an independent educational platform and is not affiliated with or endorsed by CBSE. Question papers are accessed through links to official CBSE resources and are not hosted by QuizCluster.